Optics B/C

hexagonaria · Post by **hexagonaria** » Mon Jan 30, 2012 3:55 pm

JSGandora wrote:The target can be placed not at the center?

Yes, it can be anywhere on the back wall of the box. that's what makes it potentially tricky.

hexagonaria · Post by **hexagonaria** » Mon Jan 30, 2012 4:01 pm

cngu23 wrote:
JSGandora wrote:The target can be placed not at the center?
Haven't really checked the rules on this but

for the laser shoot, which variables are changed, the location of the target, or the location of the obstacle, and how many obstacles are there?
Is there a predetermined size for the box too?

I am thinking about premaking a few mirror placement models that can work for almost any placement of the object or target. Might that be helpful, or do they not allow you to use notes or anything when making calculations?
Thank you.

I forget the box dimensions, its in the rules I'll look it up later. But as for the variables, they can change the target location and the obstacle positions. I believe at least one obstacle is required to be directly between the laser and the target. I think you can bring notes and calculators, but I didn't need them since I used my templates.

JSGandora · Post by **JSGandora** » Mon Jan 30, 2012 4:10 pm

The dimentions are $56\pm1\text{ cm}\times 35\pm1\text{ cm}$ .

chalker · Post by **chalker** » Mon Jan 30, 2012 7:07 pm

cngu23 wrote: Haven't really checked the rules on this but

This is never a good thing if you actually intend to compete in this event. Get yourself a copy and study them.

SciBomb97 · Post by **SciBomb97** » Mon Jan 30, 2012 9:03 pm

For div. B nerds out there, do you guys study stuff like the thin-lens equation and stuff??? I feel like I'm studying in too much detail...

Infinity Flat · Post by **Infinity Flat** » Mon Jan 30, 2012 11:03 pm

SciBomb97 wrote:For div. B nerds out there, do you guys study stuff like the thin-lens equation and stuff??? I feel like I'm studying in too much detail...

For division B, you probably don't have to know the thin-lens equation, but I'd be familiar with the Gaussian Lens Formula.

tuftedtitmouse12 · Post by **tuftedtitmouse12** » Tue Jan 31, 2012 4:41 am

The thin-lens equation is I/f + I/Do = I/Di right? (Just double checking here...)

cngu23 · Post by **cngu23** » Tue Jan 31, 2012 5:06 am

tuftedtitmouse12 wrote:The thin-lens equation is I/f + I/Do = I/Di right? (Just double checking here...)

i thought it was
1/do + 1/di = 1/f

hexagonaria · Post by **hexagonaria** » Tue Jan 31, 2012 5:15 am

cngu23 wrote:
tuftedtitmouse12 wrote:The thin-lens equation is I/f + I/Do = I/Di right? (Just double checking here...)
i thought it was
1/do + 1/di = 1/f

Thats what i've been using.. 1/f=1/di plus 1/do

Post by **Schrodingerscat** » Tue Jan 31, 2012 5:29 am

Edit: Misread conservation, the correct equation seems to be 1/do+1/di=1/f.

Scioly.org

Optics B/C

Re: Optics B/C

Re: Optics B/C

Re: Optics B/C

Re: Optics B/C

Re: Optics B/C

Re: Optics B/C

Re: Optics B/C

Re: Optics B/C

Re: Optics B/C

Re: Optics B/C

Connect

Learn

Get Involved

About

Disclaimer