No, I didn't fall, I was just checking if gravity still works
edit: accidentally typed an extra letter
Aristocract from a song in a musical
"Xtud vfs'eu hwaaodi od w hfeukn wdm ntueu'k dfrfmv wefsdm, mf vfs ulue euwaav yewkt, fe ulud qwpu w kfsdm?"
First time, hope I didn't screw up
MY FAVORITE MY FAVORITE MY FAVORITE
WHEN YOU'RE FALLING IN A FOREST AND THERE'S NOBODY AROUND, DO YOU EVER REALLY CRASH OR EVEN MAKE A SOUND?
Since it might be more helpful than the actual answer, here's my solve path:
Start with YOU'RE and you should be able to deduce WHEN before it given the position of the E. At this point I reconned the quote because I love Dear Evan Hansen. Realistically you could go for THERE'S, or if you're going sequentially you may notice that the third word ends in ING and the next word is IN so to can assume ING and go from there. Another option is going filling in EVER/EVEN and then you should also get REALLY. After that you should be set.
Decode this Affine about flying
C MTSE JGL DM RWT DM AU XHCQJD SGRRUCTQ HCOE DIM ZWRRCDM DJCTQK ZESGWKE AU QGDE IGK TEBD DM WRZGT DMRDCHHG
Re: Codebusters B/C
Posted: September 20th, 2022, 7:04 pm
by bangtanarmy7
I'm most likely wrong, but aren't the a and b values usually given for affines?
Re: Codebusters B/C
Posted: September 21st, 2022, 8:29 am
by knightmoves
Wouldn't any affine decryption qualify as monoalphabetic substitution with random alphabet, making this an aristocrat under 3ei(1)?
Re: Codebusters B/C
Posted: September 21st, 2022, 8:31 am
by knightmoves
knightmoves wrote: ↑September 21st, 2022, 8:29 am
Wouldn't any affine decryption qualify as monoalphabetic substitution with random alphabet, making this an aristocrat under 3ei(1)?
Actually, this one doesn't - ACA's definition of monoalphabetic substitution includes the requirement that no letter encodes to itself.