Scioly.org

MattChina wrote:I guess Ill ask one.
Lets start of easy:
If i drop a ball off a cliff of 100m. Assuming we are on earth and there is no air resistance, how long will it take for the ball to reach the ground.

4.5 seconds

Adi1008 wrote:

MattChina wrote:I guess Ill ask one.
Lets start of easy:
If i drop a ball off a cliff of 100m. Assuming we are on earth and there is no air resistance, how long will it take for the ball to reach the ground.

Answer (Click to Show Hidden Text)

4.5 seconds

MattChina wrote:

Adi1008 wrote:

MattChina wrote:I guess Ill ask one.
Lets start of easy:
If i drop a ball off a cliff of 100m. Assuming we are on earth and there is no air resistance, how long will it take for the ball to reach the ground.

Answer (Click to Show Hidden Text)

4.5 seconds

yep. Your Turn.

Adi1008 wrote: Suppose an object of mass m is falling such that air resistance cannot be neglected. The object is roughly spherical and quite small, so the drag force is directly proportional to its velocity (viscous drag force, F = bv, where b is a constant of proportionality with units kg/s).

a. What is the acceleration of the object, in terms of m, g, b, and instantaneous velocity v?
b. What is the velocity of this object at any given instant?
c. What is the terminal velocity of the object, in terms of m, g, and b?

a. g + bv/m
b. gt+bd/m, where d is the distance that the object has fallen so far (not sure how to do it just in terms of time)
c. mg/b

UTF-8 U+6211 U+662F wrote:

Adi1008 wrote: Suppose an object of mass m is falling such that air resistance cannot be neglected. The object is roughly spherical and quite small, so the drag force is directly proportional to its velocity (viscous drag force, F = bv, where b is a constant of proportionality with units kg/s).

a. What is the acceleration of the object, in terms of m, g, b, and instantaneous velocity v?
b. What is the velocity of this object at any given instant?
c. What is the terminal velocity of the object, in terms of m, g, and b?

Answer (Click to Show Hidden Text)

a. g + bv/m
b. gt+bd/m, where d is the distance that the object has fallen so far (not sure how to do it just in terms of time)
c. mg/b

I got the same answer as UTF for Part A and C. For Part B, I got:

v=\frac{mg(1-e^{-bt/m})}{b}

EDIT: For some reason the LaTeX isn't working so I just posted the code

UTF-8 U+6211 U+662F wrote:Okay, lemme restart this thread.

If velocity is the change in position with respect of time and acceleration is the change in velocity with respect of time, then what is the change in acceleration with respect of time.

Also note the new

Code: Select all

[answer]

tag

Click to Show Answer

hi

Jerk

IcsTam wrote:

UTF-8 U+6211 U+662F wrote:Okay, lemme restart this thread.

If velocity is the change in position with respect of time and acceleration is the change in velocity with respect of time, then what is the change in acceleration with respect of time.

Also note the new

Code: Select all

[answer]

tag

Click to Show Answer

hi

Click to Show Answer

Jerk