Re: Astronomy C
Posted: February 27th, 2015, 4:21 pm
The equation sum of masses = a^3 / p^2 is a slightly more general formula using units of solar masses, AU, and years. In fact, it's not the most general formula, which is a^3 / p^2 = G*sum of masses / (4pi)^2, all in MKS units. Unfortunately, for the first part due to constrained information you need to approximate the whole mass of the system as the mass of the star alone, which is a pretty good approximation.
What this means is you actually make an incorrect assumption in saying semi-major axis of orbit is given, it's actually derived. For part a you are ignoring that mass, and by part c that distance is still derived and not given. So basically when you add in the planet mass, m_p, you are working with different values. To work around that, you need to derive other methods with physics! Knowing to use the ratio is really just experience, if you just google something like "exoplanet formulas" along with looking through the rules (there's stuff like spectroscopic parallax and general stellar evolution comprehension) you should get an idea of math to be asked. Beyond that it's just practice.
Now to try to make the physics slightly more clear. The problem with "plug and chug" use of equations, which I know is not your intention but kind of just happened, is that you don't think as much as you can about your options and techniques, which is why I always recommend derivation (at least it brings understanding somewhat closer). If you're an astronomer in the field, you have to be VERY careful about stuff like this. I swear, there's derivations available online for various formulas.
Now you're probably wondering still, how can we use this magic ratio if we work under that assumption? Great question! The key is...well, we work under that assumption for radial velocity (along with some others). The derivation comes from the definition of the center of mass, which allows us to say m1*x1 = m2*x2 in general (x1 and x2 are respective distances to the barycenter, or center of mass). Assumed circular velocity is 2pi*r/T, so you end up getting v1 and v2 (the 2pis cancel), and so the ratio then becomes what we've been saying. An alternative way is just through conservation of momentum, which directly produces the equation. There is even something called the binary system mass ratio, but that requires ratio of masses (or velocities, distances), which again follows the same issue with keeping consistent assumptions. Both this and Kepler's third law at their base come from a derivation that can simply use Newton's third law (that is forces that form reaction pairs are equal, like the mutual gravitational force felt by both bodies in orbit for this question). If it helps you, just think of the "total mass" as being put equal to the mass of the star (so you would have a slightly less massive star to input the orbiting planet).
You may now worry all answers are wrong, but everything has error. This error from ignoring planetary mass in the equation of Kepler's third law often produces an error of about 0.001%, which is hardly as much as the errors from non-circular orbit or inclination.
Does that make more sense?
What this means is you actually make an incorrect assumption in saying semi-major axis of orbit is given, it's actually derived. For part a you are ignoring that mass, and by part c that distance is still derived and not given. So basically when you add in the planet mass, m_p, you are working with different values. To work around that, you need to derive other methods with physics! Knowing to use the ratio is really just experience, if you just google something like "exoplanet formulas" along with looking through the rules (there's stuff like spectroscopic parallax and general stellar evolution comprehension) you should get an idea of math to be asked. Beyond that it's just practice.
Now to try to make the physics slightly more clear. The problem with "plug and chug" use of equations, which I know is not your intention but kind of just happened, is that you don't think as much as you can about your options and techniques, which is why I always recommend derivation (at least it brings understanding somewhat closer). If you're an astronomer in the field, you have to be VERY careful about stuff like this. I swear, there's derivations available online for various formulas.
Now you're probably wondering still, how can we use this magic ratio if we work under that assumption? Great question! The key is...well, we work under that assumption for radial velocity (along with some others). The derivation comes from the definition of the center of mass, which allows us to say m1*x1 = m2*x2 in general (x1 and x2 are respective distances to the barycenter, or center of mass). Assumed circular velocity is 2pi*r/T, so you end up getting v1 and v2 (the 2pis cancel), and so the ratio then becomes what we've been saying. An alternative way is just through conservation of momentum, which directly produces the equation. There is even something called the binary system mass ratio, but that requires ratio of masses (or velocities, distances), which again follows the same issue with keeping consistent assumptions. Both this and Kepler's third law at their base come from a derivation that can simply use Newton's third law (that is forces that form reaction pairs are equal, like the mutual gravitational force felt by both bodies in orbit for this question). If it helps you, just think of the "total mass" as being put equal to the mass of the star (so you would have a slightly less massive star to input the orbiting planet).
You may now worry all answers are wrong, but everything has error. This error from ignoring planetary mass in the equation of Kepler's third law often produces an error of about 0.001%, which is hardly as much as the errors from non-circular orbit or inclination.
Does that make more sense?