Thermodynamics B/C

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Re: Thermodynamics B/C

Post by JoeyC »

Whoops, didn't see the second question.
Why are some qualities represented by capital letters and others lowercase. Give 3 examples of each.
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Re: Thermodynamics B/C

Post by Crimesolver »

JoeyC wrote:Whoops, didn't see the second question.
Why are some qualities represented by capital letters and others lowercase. Give 3 examples of each.
Some qualities are represented in capitals and some lowercase to create less confusion in which symbol represents what. For example, T represents temperature while t represents time. s represents seconds while S represents entropy. K represents Kelvin while k represents thermal conductivity.
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Re: Thermodynamics B/C

Post by JoeyC »

First, when answering use

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Second, partially correct; it is correct, but I was looking for capital letters indicate extensive qualities while lowercase intensive in Thermo (intensive=mass dependent qualities) Alright, your turn!
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Re: Thermodynamics B/C

Post by Crimesolver »

Nice nice! What would be the change in volume if a steel cube was originally 50cm3 and was heated from 50 degrees C to 80 degrees C?
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Re: Thermodynamics B/C

Post by Steuben42 »

[math]\Delta V = 3\Alpha V_0\Delta T[/math]
I have it in my notes that the α of steel is 13x10[sup]-6[/sup] C...
[math]\Delta V = 3(13*10^-^6 C)(50 cm^3)(80 C - 50 C)[/math]
[math]\Delta V = 0.0585 cm^3[/math]
Which with sig figs would be, I believe, 0.06 cm[sup]3[/sup].
First time answering, so please let me know if there's anything I'm doing wrong.
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Re: Thermodynamics B/C

Post by Crimesolver »

Steuben42 wrote:
[math]\Delta V = 3\Alpha V_0\Delta T[/math]
I have it in my notes that the α of steel is 13x10[sup]-6[/sup] C...
[math]\Delta V = 3(13*10^-^6 C)(50 cm^3)(80 C - 50 C)[/math]
[math]\Delta V = 0.0585 cm^3[/math]
Which with sig figs would be, I believe, 0.06 cm[sup]3[/sup].
First time answering, so please let me know if there's anything I'm doing wrong.
Yeah that's the correct answer. I should of said what the volume expansion coefficient was for steel, because it is different depending on the composition.

Your turn!
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Re: Thermodynamics B/C

Post by Steuben42 »

Neat, let's see what I've got...

While fairly accurate for certain gases, there are some that diverge slightly from predicted behavior according to the Ideal Gas Law.
1) Under what conditions is the Ideal Gas Law most accurate?
2) What is the equation that adjusts for these inaccuracies, and what are the modifications it makes to the Ideal Gas Law?
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Re: Thermodynamics B/C

Post by UTF-8 U+6211 U+662F »

Steuben42 wrote:Neat, let's see what I've got...

While fairly accurate for certain gases, there are some that diverge slightly from predicted behavior according to the Ideal Gas Law.
1) Under what conditions is the Ideal Gas Law most accurate?
2) What is the equation that adjusts for these inaccuracies, and what are the modifications it makes to the Ideal Gas Law?
1) High temperature and volume, low pressure
2) The van der Waals equation: it adjusts the pressure and volume to account for attractive forces using two additional gas variables.
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Re: Thermodynamics B/C

Post by Steuben42 »

UTF-8 U+6211 U+662F wrote:
Steuben42 wrote:Neat, let's see what I've got...

While fairly accurate for certain gases, there are some that diverge slightly from predicted behavior according to the Ideal Gas Law.
1) Under what conditions is the Ideal Gas Law most accurate?
2) What is the equation that adjusts for these inaccuracies, and what are the modifications it makes to the Ideal Gas Law?
1) High temperature and volume, low pressure
2) The van der Waals equation: it adjusts the pressure and volume to account for attractive forces using two additional gas variables.
Looks all good to me, your turn!
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Re: Thermodynamics B/C

Post by UTF-8 U+6211 U+662F »

Why do liquids require latent heat to vaporise?

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