Fermi Questions C

[talkingturtle101]

My Answer (Click to Show Hidden Text)

- The Pacific probably has E18 liters of water
- A sink could probably dispense 1 liter every ten seconds.
- Multiplying gives us E19 seconds, Fermi Answer of 19.

Off By A Little (Click to Show Hidden Text)

- The Pacific actually has a volume of 660,000,000 km^3, and 1 km^3 is E12 liters.
- This gives a volume of 6.6E20.
- I think the one liter per ten seconds thing is accurate.
- This gives us 6.6E21, Fermi Answer of 22.

Assuming you had all the wood and metal, how many violin bows could be made using the tails of all the horses in the world?

[Ashernoel]

My Answer (Click to Show Hidden Text)

- The Pacific probably has E18 liters of water
- A sink could probably dispense 1 liter every ten seconds.
- Multiplying gives us E19 seconds, Fermi Answer of 19.

Off By A Little (Click to Show Hidden Text)

- The Pacific actually has a volume of 660,000,000 km^3, and 1 km^3 is E12 liters.
- This gives a volume of 6.6E20.
- I think the one liter per ten seconds thing is accurate.
- This gives us 6.6E21, Fermi Answer of 22.

Assuming you had all the wood and metal, how many violin bows could be made using the tails of all the horses in the world?

Isn't the volume of the Pacific Ocean FA9? From google

[Adi1008]

My Answer (Click to Show Hidden Text)

- The Pacific probably has E18 liters of water
- A sink could probably dispense 1 liter every ten seconds.
- Multiplying gives us E19 seconds, Fermi Answer of 19.

Off By A Little (Click to Show Hidden Text)

- The Pacific actually has a volume of 660,000,000 km^3, and 1 km^3 is E12 liters.
- This gives a volume of 6.6E20.
- I think the one liter per ten seconds thing is accurate.
- This gives us 6.6E21, Fermi Answer of 22.

Assuming you had all the wood and metal, how many violin bows could be made using the tails of all the horses in the world?

Isn't the volume of the Pacific Ocean FA9? From google

I think that's in km^3, while talkingturtle101 converted to liters.

[Ashernoel]

My Answer (Click to Show Hidden Text)

- The Pacific probably has E18 liters of water
- A sink could probably dispense 1 liter every ten seconds.
- Multiplying gives us E19 seconds, Fermi Answer of 19.

Off By A Little (Click to Show Hidden Text)

- The Pacific actually has a volume of 660,000,000 km^3, and 1 km^3 is E12 liters.
- This gives a volume of 6.6E20.
- I think the one liter per ten seconds thing is accurate.
- This gives us 6.6E21, Fermi Answer of 22.

Assuming you had all the wood and metal, how many violin bows could be made using the tails of all the horses in the world?

Isn't the volume of the Pacific Ocean FA9? From google

I think that's in km^3, while talkingturtle101 converted to liters.

Ohhh in the actual event would we memorize most of these common values if we wanted to be competitive at it?

[talkingturtle101]

You could either memorize them or know enough to reasonably estimate.

[Raleway]

You could either memorize them or know enough to reasonably estimate.

Or you could be a god and internally know how long 100 miles is on a globe and then mentally be able to calculate to a magnitude distances (which I feel is more useful). Memorizing important distances and populations is part of this event though.

[Raleway]

How many standard Mountain Dew cans would be needed (the ones in a 6 pack) to reach the volume of Mount Everest (yay more packing)

CHALLENGE: Combining all the volumes of buildings considered part of Stanford, how many sets of those would be required to fill up all the planets of the solar system?
*I think I made fact searching too hard*

[NeilMehta]

How many standard Mountain Dew cans would be needed (the ones in a 6 pack) to reach the volume of Mount Everest (yay more packing)

CHALLENGE: Combining all the volumes of buildings considered part of Stanford, how many sets of those would be required to fill up all the planets of the solar system?
*I think I made fact searching too hard*

My desperate attempt:
Height = E4 m(?)
Imagining what mt. Everest looks like, I'd say radius of base is also E4
cone volume = 1/3 * pi * r^2 * h
That should be about E12 m^3 in volume of mt everest
A mt. dew can is about .2m x .1m x .1m which should be about E-2
Final answer is E^14?

Update: the challenge is still up, although if no one will do it I'll post a new question

[Raleway]

@Neil
Wahn wahn wahnnnn (I can't do the sound right lol)
Fermi Result: 6

TRY THE CHALLENGE ))

[NeilMehta]

How many standard Mountain Dew cans would be needed (the ones in a 6 pack) to reach the volume of Mount Everest (yay more packing)

CHALLENGE: Combining all the volumes of buildings considered part of Stanford, how many sets of those would be required to fill up all the planets of the solar system?
*I think I made fact searching too hard*

Wow, looks like that one was really off...
Alright challenge attempt...

This was all a big mistake (Click to Show Hidden Text)

Okay so i have literally no idea how big Stanford is but i'll take a random guess that they're something about E4 m^3 each and lets say there's like E3 of them (these guesses really are terrible, wow...)
Anyway that's a total volume of E7 m^3 hmm
So i know earth radius is like 6E6 m, and for estimation's sake, lets say all of the terrestrial planets are E6 m in diameter on average (a bad, bad idea)
Lets also say all of the Jovian planets have an average radius of about E8 m, which is again a bad idea
So the area of the terrestrial planets would be:
4*E6^3=4E18 times four for all four planets to get E19ish
And Jovian planets:
4*E8^3=4E24 times four for all planets to get just about E25
At this point I'm realizing how I should've totally ignored the terrestrial planets in the first place, oops....
So from E25 m^3 / E7 m^3 ill go with about E18 although this really doesn't sound right, welp
Final answer: E18

aaaaand here's the actual answer...

So turns out it was a bigger mistake then i expected (Click to Show Hidden Text)

So apparently the volume of the big planets is E18 total
However, Stanford really only has E3 buildings, so i suppose i was right on that
Now to estimate the volume of all buildings in Stanford, I took a look at Google Earth's 3D model of the place, and it seems that the average building is 20m*5m*4m for just about E2 m^3 per building
So if that's E5 m^3 for all buildings, the actual answer is something like E13, so still pretty off...
Final true answer: E13(???)