Re: Astronomy C
Posted: March 6th, 2019, 9:05 pm
Yup. I didn't specify whether it was a galaxy with a single cepheid or not but that's what I meant so props to you.
Your turn
Your turn
Normally I don't check these, but it's simpler to just say the galaxy contains a cepheid, and you measure that cepheid's apparent magnitude to be whatever it is (to everyone...I figure people "get this", but it helps to be explicit instead of "the galaxy is a single cepheid" when reading the answers above...really not a big deal). BUT that leads to the interesting question of how you separate the apparent brightness of cepheids in a galaxy from other stars, or where that might be relevant...but you should probably ask a different question you're actually wondering since that's kinda vague. There's all kinds of issues you get into when you're actually trying to go from a galaxy's overall apparent brightness to that of stars, but I'm honestly not a pro at it.SciolyHarsh wrote:Yup. I didn't specify whether it was a galaxy with a single cepheid or not but that's what I meant so props to you.
Your turn
Not sure about my answer but may as well try to revive the thread.ET2020 wrote:Two stars orbit in a binary system. Star A's orbit traces a circle with an apparent radius of 600 milliarcseconds, while star B's orbital traces a circle with an apparent radius of 200 milliarcsecond. Star A is a main sequence star with a luminosity of 4.2 solar luminosities and an apparent magnitude of 7.65. Find the mass of Star B and its distance from the center of mass of the binary system.
So first I made the absolute magnitude of star A to be 3.21, which makes the distance to star A 77.2 pc. Using something I learned from a test, if the star is 77.2 pc away, then one arcsecond of distance should be 77.2 AU. So the radius of Star A is 600 mas, .6 arcsec, or 46.3 AU, and by that logic, Star B is .2 arcsec away from the center of mass, making it [b]15.4 AU[/b], which [b]should[/b] be the first answer (?) As for the mass of Star B, I dont have an exact answer. The mass of Star B must be 3 times greater than Star A because it is 3 times closer to the center of mass, but I dont know how i could figure that out without the period, which i could use to find the combined mass of the system using MsubA + MsubB = a^3/p^2, but im unsure about my value for a (30.4 AU?) and I have no idea how to get p. So, my answer is gonna be [b]3 times greater than the mass of Star A. Anywhere close? We'll see ig haha[/b]
Giantpants wrote:Not sure about my answer but may as well try to revive the thread.ET2020 wrote:Two stars orbit in a binary system. Star A's orbit traces a circle with an apparent radius of 600 milliarcseconds, while star B's orbital traces a circle with an apparent radius of 200 milliarcsecond. Star A is a main sequence star with a luminosity of 4.2 solar luminosities and an apparent magnitude of 7.65. Find the mass of Star B and its distance from the center of mass of the binary system.
So first I made the absolute magnitude of star A to be 3.21, which makes the distance to star A 77.2 pc. Using something I learned from a test, if the star is 77.2 pc away, then one arcsecond of distance should be 77.2 AU. So the radius of Star A is 600 mas, .6 arcsec, or 46.3 AU, and by that logic, Star B is .2 arcsec away from the center of mass, making it [b]15.4 AU[/b], which [b]should[/b] be the first answer (?) As for the mass of Star B, I dont have an exact answer. The mass of Star B must be 3 times greater than Star A because it is 3 times closer to the center of mass, but I dont know how i could figure that out without the period, which i could use to find the combined mass of the system using MsubA + MsubB = a^3/p^2, but im unsure about my value for a (30.4 AU?) and I have no idea how to get p. So, my answer is gonna be [b]3 times greater than the mass of Star A. Anywhere close? We'll see ig haha[/b]
Use the mass luminosity relationship. For a main sequence star from a mass of .43 to 2 sm (Relationships are different with different masses), the equation is luminosity is approximently equal to mass^4. Luminosity of star A is 4.2, the fourth root of that is 1.43 which would be mass of star A in solar masses. Then multiplied by 3 to get [b]4.29[/b] solar masses for mass of star B