Page 5 of 6

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 25th, 2014, 1:23 am
by hmath729
Yep, your turn.

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 25th, 2014, 1:28 am
by hmath729
Just wondering, is this how to hide an answer?
Stuff inside

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 26th, 2014, 8:49 pm
by PicturePerfect
hmath729 wrote:Just wondering, is this how to hide an answer?
Stuff inside
yes :)

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 27th, 2014, 6:06 am
by hmath729
Here's a two-parter.
  1. Describe this person's karyotype in the form of (46, XY)
  2. Is there anything wrong with this person? If so, what is the name of the disorder?
Image

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 27th, 2014, 6:43 am
by emescferrall
Not sure about what you mean in the first part, but here's the answer to the second part . . . [hide]This male has Down Syndrome, also called Trisomy 21.[/hide]

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 27th, 2014, 4:22 pm
by hmath729
Correct, your turn. Just remember that the format for hiding is

Code: Select all

[hide]Stuff outside|Stuff inside[/hide]

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 27th, 2014, 9:35 pm
by PicturePerfect
47, XY, +21

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 28th, 2014, 2:23 am
by hmath729
Yep. :P

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 28th, 2014, 7:08 am
by emescferrall
Okay. Here goes: A male with blood type A marries a woman with blood type AB. They have four children. List the genotypes and phenotypes of these four children.

Re: Heredity B/Designer Genes C Question Marathon

Posted: February 28th, 2014, 12:47 pm
by vennowsah
Since the genotype of the male isn't specified, he can have two possible genotypes.
If the male has a genotype of AA, then the four children would be:
Genotype- 2:2 (50% AA, 50% AB)
Phenotype- 2:2 (50% type A, 50% type AB)

If the male has a genotype of AO, then the four children would be:
Genotype- 1:1:1:1 (25% AA, 25% AO, 25% AB, 25% BO)
Phenotype: 2:1:1 (50% type A, 25% type AB, 25% type B)