Complexity wrote:Complexity wrote:Balsa Man wrote:Actually, with that buckling strength, bracing at 1/7 intervals with ladders and Xs should work. What interval have you been using?
Every 1/12 of the tower. At every six inches. The buckling strength is 20 for a piece. It is 15 for the rest, so less. My legs are very light, so I will take the floppy leg more bracing approach.
If you say that 1/7 will work, then I think I will reconsider my bracing interval. I want a little more to be safe, maybe 1/10. 1/7 worked with 20 buckling strength, but would more would probably be needed since now they all show 15.
Made the cutting jig

Complexity, there are a couple things I’m having trouble following, and/or that aren’t making sense; let’s see if we can figure them out-.
“1/7 worked with 20 buckling strength”
What interval are you using? “1/12th of the tower”
“The buckling strength is 20 for a piece. It is 15 for the rest, so less”
You say you were bracing at 1/12 interval, and say that’s every 6 inches. For a C tower, leg length will be about 61.5cm for a tower meeting the 29cm circle bonus, for one just clearing the 20cm x 20cm base opening, leg length will be around 61cm. 1/12 (your bracing interval) of 61cm is 5.08cm; braced points every 5.08cm along the legs. So, even if you meant 6cm, instead of inches, bracing interval number isn’t correct. The braced interval for 1/7, on a 61cm leg is 61/7 = 8.7cm.
Let’s review some calculations. 1/12 interval first.
For (36”) leg sticks with scale reading from single finger push-down testing ; scale reading of 20gr. That’s buckling strength under pinned/pinned end conditions. So, multiply that by 2.3 (to calculate buckling strength when in fixed/fixed end conditions – see discussion in the thread ‘measuring/using buckling strength-new info’) , you get 46gr. So, how does bracing a stick 36” long that buckles at 20gr to shorter intervals (5.08cm) increase that? 5.08cm is 0.0555 of 91.6cm (36”). Inverse square relationship tells us: 1/0.0555 squared is 325.135. 46gr x 325.135 is 14,926gr. That’s of course, WAY over what’s needed (3810, plus a safety factor; at a 20% SF, that takes us to 4572gr). But, still way over; >3x what you need. Change the 36” buckling strength measured on the scale to 15 (instead of 20). Times 2.3, that becomes 34.5gr. 34.5 x 325.135 = 11,217gr. Again, way over; >twice what you need.
Ok, lets run the same numbers for 1/7 interval bracing. 1/7 of 61 is 8.7cm 8.7 is 0.095 of 91.6. 1/0.095 squared is 110.8. For a 36” stick testing on the scale at 20gr, 20 x 2.3 = 46, and 46 x 110.8 = 5,097gr substantially over 3,810, and 4,572.
If the 36” buckling scale reading is 15, 2.3 x 15 = 34.5gr. 34.5gr x 110.8 = 3,822gr, just a hair below design load of 3,810gr, no safety factor = will likely not get you to a 15kg tower load. So, with 3/32nd”, 36” sticks that only test at 15, you’ll need to take bracing interval down to 1/8.
1/8 of 61cm = 7.625cm. 7.635cm is 0.0832 of 91.6cm. 1/0.0832 squared = 144.315. 34.5gr x 144.315 = 4,979gr; enough, with a safety factor of a bit over 20%.
The numbers say using 36” sticks testing on the scale at 15gr for legs, braced at 1/8 intervals should work fine.
But, one other important thing to check. Calculations above are for legs. One other design factor that has to work, too; the buckling strength of the ladders (especially the lower (longer) ladders.
I think from what you said, you used 3/32nd” stick, scale testing at 15g. As I’ve discussed, in a ladders and Xs setup, the design load the ladders need to carry is only about 1kg. I’ve explained this is …an experience-based number (while the leg design load is an actually calculated number). Calculating ladder buckling strength (for 36” stick testing at 15gr) is done the same was as for legs. Without taking the time to draw it up, not sure what your lowest ladder length is; I’m guessing a bit under 19cm, I’ll use 18.75. 18.75 is 0.205 of 91.6cm ; 1/0.205 squared is 23.87. 23.87 x 34.5gr = 824gr. Because the 1kg ‘design load’ is just a working estimate, this might work, but I suspect it won’t. At ladder lengths at/below about 16.5cm, it will. For a ladder at 18.75, you’ll need a 36” test value of 22-23gr.
I’m curious; did you build/test tower at the 20 gr at 36” braced at 1/12 interval; what did it weigh, what did it carry? Same question on the one braced at 1/7 that ‘worked.’
Hope this helps, and helps understand the inverse square calculation. Good luck!