Thermodynamics B/C

Post by **Froggie** » Thu Jan 11, 2018 8:06 am

Pizzacats wrote:What is the equation from kelvin to Celsius please!!??

T(°C) = T(K) - 273.15

Pizzacats · Post by **Pizzacats** » Thu Jan 11, 2018 8:12 am

Thank u Froggie.

Pizzacats · Post by **Pizzacats** » Thu Jan 11, 2018 8:14 am

Wait, I always thought it was T(K)= T(C) - the 2 hundred something point 15

Pizzacats · Post by **Pizzacats** » Thu Jan 11, 2018 8:16 am

And is there any other heat unit than Joule? Because Thais the only one I know

Pizzacats · Post by **Pizzacats** » Thu Jan 11, 2018 8:18 am

*This
Not Thais

About me · Post by **pikachu4919** » Thu Jan 11, 2018 8:26 am

Pizzacats wrote:Wait, I always thought it was T(K)= T(C) - the 2 hundred something point 15

Yes, 273.15. But no, T(K) = T(C) + 273.15.

Pizzacats wrote:And is there any other heat unit than Joule? Because Thais the only one I know

Yes, there are many. There’s the calorie, there’s the BTU, there’s the watt, and there are others you could derive from other existing units as well

Userpage · Post by **Unome** » Thu Jan 11, 2018 8:32 am

Pizzacats wrote:Wait, I always thought it was T(K)= T(C) - the 2 hundred something point 15

The Kelvin value is always larger than the Celsius equivalent, so T(K) = T(C) + 273.15

kendreaditya · Post by **kendreaditya** » Thu Jan 11, 2018 10:07 am

You can find all the conversion for temperatures here:
https://en.wikipedia.org/wiki/Conversio ... emperature

vjindal · Post by **vjindal** » Thu Jan 11, 2018 1:56 pm

Pizzacats wrote:What is the equation from kelvin to Celsius please!!??

K - 273.15 = C

Where K is degrees Kelvin and C is degrees Celsius.

Alex-RCHS · Post by **Alex-RCHS** » Thu Jan 11, 2018 2:16 pm

Honestly why is this even a discussion, you can google this in seconds.

Scioly.org