Correct. Your turn!Riptide wrote:By the conservation of angular momentum, Iw = Iw (of course assuming frictionless surfaces). When the moment of inertia is cut in half, the angular velocity doubles, resulting in a angular velocity of 4π rad/s. After 3 seconds, he has traveled 12π radians, or 6 revolutions (1 revolution = 2π yay unit circle).Justin72835 wrote:Alright. Nathan Chen is an 18-year-old American figure skater competing at the 2018 Winter Olympics. During one of his tricks, he begins spinning around at a steady 2π rad/s. Bringing his arms in toward his chest, Chen is able to decrease his moment of inertia by half. After doing this, how many revolutions does Chen complete after 3 seconds of spinning? Assume that because the ice is frictionless and that his angular velocity does not decrease.Riptide wrote:
Wow that was quick. Nice job! Sorry for not mentioning the pressure, you made the right assumption for keeping them the same. Your turn!
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Re: Hovercraft B/C
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Re: Hovercraft B/C
Consider a satellite orbiting Earth elliptically. Find the ratio of its speed at perihelion to that at aphelion.Justin72835 wrote:Correct. Your turn!Riptide wrote:By the conservation of angular momentum, Iw = Iw (of course assuming frictionless surfaces). When the moment of inertia is cut in half, the angular velocity doubles, resulting in a angular velocity of 4π rad/s. After 3 seconds, he has traveled 12π radians, or 6 revolutions (1 revolution = 2π yay unit circle).Justin72835 wrote: Alright. Nathan Chen is an 18-year-old American figure skater competing at the 2018 Winter Olympics. During one of his tricks, he begins spinning around at a steady 2π rad/s. Bringing his arms in toward his chest, Chen is able to decrease his moment of inertia by half. After doing this, how many revolutions does Chen complete after 3 seconds of spinning? Assume that because the ice is frictionless and that his angular velocity does not decrease.
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Re: Hovercraft B/C
Riptide wrote:Consider a satellite orbiting Earth elliptically. Find the ratio of its speed at perihelion to that at aphelion.Justin72835 wrote:Correct. Your turn!Riptide wrote:
By the conservation of angular momentum, Iw = Iw (of course assuming frictionless surfaces). When the moment of inertia is cut in half, the angular velocity doubles, resulting in a angular velocity of 4π rad/s. After 3 seconds, he has traveled 12π radians, or 6 revolutions (1 revolution = 2π yay unit circle).
[math]r_{a}/r_{p}[/math]
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Re: Hovercraft B/C
Guess that was too easy. Your turn!Adi1008 wrote:Riptide wrote:Consider a satellite orbiting Earth elliptically. Find the ratio of its speed at perihelion to that at aphelion.Justin72835 wrote: Correct. Your turn![math]r_{a}/r_{p}[/math]
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Re: Hovercraft B/C
A 2kg rock is thrown straight downwards from a height of 10 meters with a velocity of 5 m/s. When it lands, it sinks 0.5 meters into the snow below. What is the average force between the rock and the snow as the rock is sinking?Riptide wrote:Guess that was too easy. Your turn!Adi1008 wrote:Riptide wrote:
Consider a satellite orbiting Earth elliptically. Find the ratio of its speed at perihelion to that at aphelion.[math]r_{a}/r_{p}[/math]
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Re: Hovercraft B/C
Adi1008 wrote:A 2kg rock is thrown straight downwards from a height of 10 meters with a velocity of 5 m/s. When it lands, it sinks 0.5 meters into the snow below. What is the average force between the rock and the snow as the rock is sinking?Riptide wrote:Guess that was too easy. Your turn!Adi1008 wrote:[math]r_{a}/r_{p}[/math]
The combined mechanical energy of the system is found by adding its initial kinetic and potential energy, which gives 221 J. Since it travels a distance of 0.5 meters when slowing down, you can use Fd = W, which gives 442 N as the net force acting on the object. Now you can set up a net force equation: Fnet = Fsnow - Fg, where Fsnow = 461.6 N. Final Answer: 461.6 N
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Re: Hovercraft B/C
Looks good to me; your turn!Justin72835 wrote:Adi1008 wrote:A 2kg rock is thrown straight downwards from a height of 10 meters with a velocity of 5 m/s. When it lands, it sinks 0.5 meters into the snow below. What is the average force between the rock and the snow as the rock is sinking?Riptide wrote:
Guess that was too easy. Your turn!The combined mechanical energy of the system is found by adding its initial kinetic and potential energy, which gives 221 J. Since it travels a distance of 0.5 meters when slowing down, you can use Fd = W, which gives 442 N as the net force acting on the object. Now you can set up a net force equation: Fnet = Fsnow - Fg, where Fsnow = 461.6 N. Final Answer: 461.6 N
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Re: Hovercraft B/C
A ball of mass 3kg is suspended from a 20m long massless rope. A spherical bullet of mass 50g is fired at the ball with a velocity of 450m/s and they collide elastically. Determine the angle formed by the rope and vertical once the ball has reached its maximum height.Adi1008 wrote: Looks good to me; your turn!
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Re: Hovercraft B/C
Since this is an elastic collision, the velocity of the ball after the collision is 2m1/(m1+m2)*v1, resulting in a velocity 14.8 m/s. Using the conservation of energy, we get a change in height of 11.1 meters. Drawing a diagram of this makes it easy to solve for the angle, which is 63.6 degrees.Justin72835 wrote:A ball of mass 3kg is suspended from a 20m long massless rope. A spherical bullet of mass 50g is fired at the ball with a velocity of 450m/s and they collide elastically. Determine the angle formed by the rope and vertical once the ball has reached its maximum height.Adi1008 wrote: Looks good to me; your turn!
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Re: Hovercraft B/C
Great work! Your turn!Riptide wrote:Since this is an elastic collision, the velocity of the ball after the collision is 2m1/(m1+m2)*v1, resulting in a velocity 14.8 m/s. Using the conservation of energy, we get a change in height of 11.1 meters. Drawing a diagram of this makes it easy to solve for the angle, which is 63.6 degrees.Justin72835 wrote:A ball of mass 3kg is suspended from a 20m long massless rope. A spherical bullet of mass 50g is fired at the ball with a velocity of 450m/s and they collide elastically. Determine the angle formed by the rope and vertical once the ball has reached its maximum height.Adi1008 wrote: Looks good to me; your turn!
"The fault, dear Brutus, is not in our stars,
But in ourselves, that we are underlings."
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But in ourselves, that we are underlings."
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