Optics B/C

Fluorine · Post by **Fluorine** » Mon Dec 05, 2016 6:24 am

Okay question...
The apex angle of a prism is 50.0 and the index of refraction of the prism material is 1.66. Calculate the minimum deviation angle?

Post by **John Richardsim** » Mon Dec 12, 2016 12:20 pm

Fluorine wrote:Okay question...
The apex angle of a prism is 50.0 and the index of refraction of the prism material is 1.66. Calculate the minimum deviation angle?

Haven't done much with this yet so let's hope I did it right... (Click to Show Hidden Text)

39.1 degrees

Fluorine · Post by **Fluorine** » Mon Dec 12, 2016 3:21 pm

John Richardsim wrote:
Fluorine wrote:Okay question...
The apex angle of a prism is 50.0 and the index of refraction of the prism material is 1.66. Calculate the minimum deviation angle?
Haven't done much with this yet so let's hope I did it right... (Click to Show Hidden Text)
39.1 degrees

Yep you got it! The formula can be annoying to solve in reverse but as long as your careful not too bad.

Post by **John Richardsim** » Mon Dec 12, 2016 3:45 pm

Which type of lens is used to correct nearsightedness?

0ddrenaline · Post by **0ddrenaline** » Mon Dec 12, 2016 4:19 pm

John Richardsim wrote:Which type of lens is used to correct nearsightedness?

Answer (Click to Show Hidden Text)

Diverging lens. Nearsightedness is the result of light focusing before it reaches the retina, so the lens must cause the light to diverge before it hits the eye.

Post by **John Richardsim** » Mon Dec 12, 2016 5:30 pm

0ddrenaline wrote:
John Richardsim wrote:Which type of lens is used to correct nearsightedness?
Answer (Click to Show Hidden Text)
Diverging lens. Nearsightedness is the result of light focusing before it reaches the retina, so the lens must cause the light to diverge before it hits the eye.

Yep.

0ddrenaline · Post by **0ddrenaline** » Tue Dec 13, 2016 8:30 am

Light travels from a material whose index of refraction is $n_1=3.0$ into another material whose index of refraction is $n_2=7/3$ . The opposite parallel surface of the second material is exposed to the air. (a) Find the critical angle at which light will be reflected at the interface of the materials. (b) Find the angle at which the light will pass through the interface and then be reflected at the opposite surface of the second material.

Post by **John Richardsim** » Tue Dec 13, 2016 6:10 pm

0ddrenaline wrote:Light travels from a material whose index of refraction is $n_1=3.0$ into another material whose index of refraction is $n_2=7/3$ . The opposite parallel surface of the second material is exposed to the air. (a) Find the critical angle at which light will be reflected at the interface of the materials. (b) Find the angle at which the light will pass through the interface and then be reflected at the opposite surface of the second material.

Answer (Click to Show Hidden Text)

a. 51 degrees
b. 19 degrees

0ddrenaline · Post by **0ddrenaline** » Tue Dec 13, 2016 7:16 pm

John Richardsim wrote:
0ddrenaline wrote:Light travels from a material whose index of refraction is $n_1=3.0$ into another material whose index of refraction is $n_2=7/3$ . The opposite parallel surface of the second material is exposed to the air. (a) Find the critical angle at which light will be reflected at the interface of the materials. (b) Find the angle at which the light will pass through the interface and then be reflected at the opposite surface of the second material.
Answer (Click to Show Hidden Text)
a. 51 degrees
b. 19 degrees

Correct

Post by **John Richardsim** » Tue Dec 13, 2016 7:41 pm

Use c=3.00*10^8

What is the wavelength (in nm) of light with a frequency of 4.40*10^2 THz? What color of visible light does this correspond to?

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