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finagle29 wrote:I think it's about time someone answered your question

I think the differences between the acronyms and the initialisms formed by the English words are caused by the French ordering of adjectives and nouns??? (Click to Show Hidden Text)

Greenwich Mean Time, Universal Coordinated Time, Atomic International Time, Before Common Era, Common Era

finagle29 wrote:oh word order, how thine importance doth matter so. I should probably double check my word orders because some event supervisors are likely to be very unforgiving when it comes to breaking ties.

anyway

Question (Click to Show Hidden Text)

For what order chemical reaction does the half-life depend solely on rate constant?

First Order

Ionizer wrote:ok

Question (Click to Show Hidden Text)

Superman is flying at a constant speed and constant height around the Earth. Superman has a mass of 112.35 kg, and he is flying 1235.7 m above the Earth. He experiences a centripetal force of 204065.010845 N. How many seconds does it take Superman to make one rotation around the Earth? Use proper significant figures

.

since F_c = m v^2 / r, and all the terms but v are given, the solution is v = (F_c r / m)^.5. then since distance = speed*time, 2 pi r = vt
using r_e = 6378100, and adding his flying height to the earth's radius to come up with an r of 6379335.7, the answer for v is 1.0764*10^5.
then, since distance = speed*time, 2 pi r = vt and t = 2 pi r / v, so t = 372.37s
the poster above shouldn't forget sigfigs

JonB wrote:

Ionizer wrote:ok

Question (Click to Show Hidden Text)

Superman is flying at a constant speed and constant height around the Earth. Superman has a mass of 112.35 kg, and he is flying 1235.7 m above the Earth. He experiences a centripetal force of 204065.010845 N. How many seconds does it take Superman to make one rotation around the Earth? Use proper significant figures

.

From team member:

solution (Click to Show Hidden Text)

since F_c = m v^2 / r, and all the terms but v are given, the solution is v = (F_c r / m)^.5. then since distance = speed*time, 2 pi r = vt
using r_e = 6378100, and adding his flying height to the earth's radius to come up with an r of 6379335.7, the answer for v is 1.0764*10^5.
then, since distance = speed*time, 2 pi r = vt and t = 2 pi r / v, so t = 372.37s
the poster above shouldn't forget sigfigs

372.16

boomvroomshroom wrote:

Hmmm... (Click to Show Hidden Text)

~372s (using 6.38E6 as Earth's radius)
F=mv^2/r, d=2(pi)r=vt