Syo, you're going to have one pigeon of a fun time
![Razz :P](./images/smilies/icon_razz.gif)
Yeah, this means all 3 of my astro years will have been on stellar evolution, with this being the grand finaleCrazy Puny Man wrote:I saw the rules, and it looks like a combo of 2012 & 2013 all in this year.
Emitted wavelength = observed wavelength / (1 + z) = 6000/(1.2) = 5000 angstroms
Yep! thats it. Haha my bad, though I'd just join inFawnOnyx wrote:Yeah, this means all 3 of my astro years will have been on stellar evolution, with this being the grand finaleCrazy Puny Man wrote:I saw the rules, and it looks like a combo of 2012 & 2013 all in this year.
Technically, I was supposed to post a new question since I got the last one, but yeah I took forever to check this so it's cool.Emitted wavelength = observed wavelength / (1 + z) = 6000/(1.2) = 5000 angstroms
1. Tycho's SNR/B Cas. 2. 60.183 mpc. I got this using the Distance Modulus. Since type Ia supernovae have a consistent absolute magnitude of -19.6, we can plug it into the equation d=10^((m-M+5)/5). After this, you divide by 1,000,000 to get the answer in MPC.
Nice! Another thing notable that I would say is that it very well may contain our Galaxy's youngest blackhole. Your turn now, and you may want to work on your hide function.alpacas wrote:[hide] w49b, it would have been seen supernova-ing around 1000 AD, the nebula contains nickel and iron [/hide]