Justin72835 wrote:Two gases occupy two containers, A and B. The gas in A, of volume 0.14 cubic meters, exerts a pressure of 1.18 MPa. The gas in B, of volume 0.21 cubic meters, exerts a pressure of 0.82 MPa. The containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant?
0.964?
Re: Thermodynamics B/C
Posted: April 4th, 2018, 6:51 pm
by Justin72835
MattChina wrote:
Justin72835 wrote:Two gases occupy two containers, A and B. The gas in A, of volume 0.14 cubic meters, exerts a pressure of 1.18 MPa. The gas in B, of volume 0.21 cubic meters, exerts a pressure of 0.82 MPa. The containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant?
0.964?
Not quite. How did you get your answer?
EDIT: This answer is actually correct.
Re: Thermodynamics B/C
Posted: April 4th, 2018, 7:05 pm
by UTF-8 U+6211 U+662F
Justin72835 wrote:
MattChina wrote:
Justin72835 wrote:Two gases occupy two containers, A and B. The gas in A, of volume 0.14 cubic meters, exerts a pressure of 1.18 MPa. The gas in B, of volume 0.21 cubic meters, exerts a pressure of 0.82 MPa. The containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant?
0.964?
Not quite. How did you get your answer?
Using the law of partial pressures 1.18 MPa * (0.14/0.35) + 0.82 MPa * (0.21/0.35) = 0.964 MPa
Re: Thermodynamics B/C
Posted: April 4th, 2018, 7:08 pm
by MattChina
Justin72835 wrote:
MattChina wrote:
Justin72835 wrote:Two gases occupy two containers, A and B. The gas in A, of volume 0.14 cubic meters, exerts a pressure of 1.18 MPa. The gas in B, of volume 0.21 cubic meters, exerts a pressure of 0.82 MPa. The containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant?
0.964?
Not quite. How did you get your answer?
(P1V1/Vf)+(P2V2/Vf)
Re: Thermodynamics B/C
Posted: April 4th, 2018, 7:22 pm
by Justin72835
Nevermind, both of you (UTF-8 U+6211 U+662F and MattChina) are right. I messed up my calculations beforehand
Anyways, great job to both of you and sorry for the confusion! I think it's MattChina's turn now.
Re: Thermodynamics B/C
Posted: April 4th, 2018, 7:38 pm
by MattChina
Lets do this. What is the best way to increase the efficiency of a carnot engine?
Re: Thermodynamics B/C
Posted: April 5th, 2018, 4:20 pm
by Justin72835
MattChina wrote:Lets do this. What is the best way to increase the efficiency of a carnot engine?
[math]e=1-\frac{Tc}{Th}[/math]
Re: Thermodynamics B/C
Posted: April 6th, 2018, 7:32 pm
by UTF-8 U+6211 U+662F
Justin72835 wrote:
MattChina wrote:Lets do this. What is the best way to increase the efficiency of a carnot engine?
[math]e=1-\frac{Tc}{Th}[/math]
Increase the ratio of hot temperature to cold temperature
Re: Thermodynamics B/C
Posted: April 6th, 2018, 7:40 pm
by Justin72835
UTF-8 U+6211 U+662F wrote:
Justin72835 wrote:
MattChina wrote:Lets do this. What is the best way to increase the efficiency of a carnot engine?
[math]e=1-\frac{Tc}{Th}[/math]
Increase the ratio of hot temperature to cold temperature
Oh, I completely misread that question.
Re: Thermodynamics B/C
Posted: April 7th, 2018, 7:59 am
by MattChina
UTF-8 U+6211 U+662F wrote:
Justin72835 wrote:
MattChina wrote:Lets do this. What is the best way to increase the efficiency of a carnot engine?
[math]e=1-\frac{Tc}{Th}[/math]
Increase the ratio of hot temperature to cold temperature
