Re: Circuit Lab B/C
Posted: April 15th, 2019, 6:30 pm
Thank you, haha!UTF-8 U+6211 U+662F wrote: I love this drawing8.36 kiloohms?
Looks good, your turn

Thank you, haha!UTF-8 U+6211 U+662F wrote: I love this drawing8.36 kiloohms?
UTF-8 U+6211 U+662F wrote:Simplify the following logical expression in terms of only AND and OR: XOR(A, XOR(B, AND(NOT(OR(A, B)), NOT(XOR(B, NOT(AND(A, A)))))))
OR(AND(NOT(A), B), AND(B, NOT(A)))
Oops, I forgot to specify you could use NOT too. Looks right, your turn!wec01 wrote:UTF-8 U+6211 U+662F wrote:Simplify the following logical expression in terms of only AND and OR: XOR(A, XOR(B, AND(NOT(OR(A, B)), NOT(XOR(B, NOT(AND(A, A)))))))OR(AND(NOT(A), B), AND(B, NOT(A)))
wec01 wrote:
Suppose you find an LED whose datasheet contains the above graph. What value resistor should you put in series with this LED and a 5V power source in order to have a current of 20 mA going through the circuit.
Is it 175 ohms?
Not quite, but I see what you did:krasabnk wrote:wec01 wrote:
Suppose you find an LED whose datasheet contains the above graph. What value resistor should you put in series with this LED and a 5V power source in order to have a current of 20 mA going through the circuit.Is it 175 ohms?
The voltage values on the graph give the voltage drop across the LED; you need to calculate the voltage drop across the resistor before you can use Ohm's law to find it's value.
wec01 wrote:Not quite, but I see what you did:krasabnk wrote:wec01 wrote:
Suppose you find an LED whose datasheet contains the above graph. What value resistor should you put in series with this LED and a 5V power source in order to have a current of 20 mA going through the circuit.Is it 175 ohms?The voltage values on the graph give the voltage drop across the LED; you need to calculate the voltage drop across the resistor before you can use Ohm's law to find it's value.
Oh, so is it 75 ohms?
Yep, your turnkrasabnk wrote:wec01 wrote:Not quite, but I see what you did:krasabnk wrote:Is it 175 ohms?The voltage values on the graph give the voltage drop across the LED; you need to calculate the voltage drop across the resistor before you can use Ohm's law to find it's value.Oh, so is it 75 ohms?
Think variables and complements