If you simply solve the equation 47.4435 + 50* 26/x = 34 + 50* 35/x, you would get x = 33.47.., but by assuming the difference between the two teams is 2 points, you solve 47.4435 + 50* 26/x - 2 = 34 + 50* 35/x, which gives you x = 39.32... However, with one of these teams getting 35 points on the test, the minimum of the max score must be 35. At least that's what I think the thought process is.Adi1008 wrote:Could you explain how you got the 35-39 range for the test? Quickly looking on Wolfram Alpha, it seems like the max test score just has to be more than 33ishkenniky wrote:Our B team got a mass score of 1860, time of 12.4 ==> 47.4435 on build. Our A team got a full mass score and a time score of 9 ==> 34 on buildjkang wrote: Troy destroyed everyone in terms of the test, according to the supervisor.
Our A team got a 35 on test, our B team got a 26.
B team ended up 7th, A was 8th.
therefore 47.4435 + 50* 26/x is slightly larger than 34 + 50* 35/x (let's say the difference is 2 points, which is probably being somewhat generous)
Thus the max score is between 35 and 39
Plus, since Troy destroyed everyone in terms of the test, I would guess the max score to be in the 40s at least (which you will get solutions to if you assume that the point difference between the two AB teams is greater than 2). For instance, if you assume a point difference of 3, the minimum for the max test score already becomes 44 (round up) and increases more as this point difference increases.