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Justin72835 wrote:

UTF-8 U+6211 U+662F wrote:

Justin72835 wrote:

Take 2.0 (Click to Show Hidden Text)

[math]P_1=\frac{mg}{t}=\frac{1*9.8}{1}=9.8W[/math]

Next, find the centripetal force acting on the hovercraft:

[math]F_c=m\frac{v^2}{r}=1*\frac{6^2}{14}=2.57N[/math]

[math]P_2=\frac{F_c}{t}=2.57W[/math]

Adding the two gives an answer of [b]12.37 W[/b].

Hope this is right   :oops:

Almost (Click to Show Hidden Text)

Do the hovercraft fans power the centripetal force or does the tension in the wire?

Final effort (Click to Show Hidden Text)

Is it just 9.8 W?

UTF-8 U+6211 U+662F wrote:Yep Of course, it would be more if I remembered to specify a coefficient of friction

Justin72835 wrote: A uniform 0.4 m long stick rotates freely about a horizontal axis through one of its ends. It is released at an unknown angle to the vertical. When it hangs straight down, the speed of the tip of the stick is 3.5 m/s. How large is the unknown angle?

UTF-8 U+6211 U+662F wrote:

Justin72835 wrote: A uniform 0.4 m long stick rotates freely about a horizontal axis through one of its ends. It is released at an unknown angle to the vertical. When it hangs straight down, the speed of the tip of the stick is 3.5 m/s. How large is the unknown angle?

Kind of confused here. Might be asking too much, but could you draw a picture?

UTF-8 U+6211 U+662F wrote:Ohh, I see.

Click to Show Answer

Not really sure since I still haven't quite wrapped my head around rotational stuff.

EDIT: Over-complicated things the first attempt

UTF-8 U+6211 U+662F wrote:Cool (finally!)

A 1 lb point mass is held up by two ideal ropes. One rope is vertical and 55 cm long. The other is at an angle from the vertical rope. It is attached to the same "ceiling" as the other rope, so it looks something like this:

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---------------------
|   /
|  /
| /
|/
O

Imagine you suddenly decrease the length of the rope to the right by half of the length of the rope to the left. Find the tension in each rope (magnitude and direction) after the system reaches static equilibrium if the angle between them was originally
a) as close to 0 degrees as possible
b) 30 degrees
c) 45 degrees
d) 60 degrees
e) as close to 90 degrees as possible

EDIT: Unfortunately, I made an error when I first did this problem, and the algebra is more complicated than I thought (meaning very time-consuming). Thus, I will ask another problem :/

Three masses are held up to a ceiling by three ropes, like so:

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___
 |
 O
 |
 O
 |
 O

The ball on top has a mass of 5 kg, the ball in the middle 3 kg, the ball on the bottom 1 kg. Assuming the ropes are ideal, find the tension in each rope.

Going from top to bottom, the tensions are as follows:

[math]Tension_1=(5+3+1)*9.8=88.2N[/math]

[math]Tension_2=(3+1)*9.8=39.2N[/math]

[math]Tension_3=(1)*9.8=9.8N[/math]

Essentially, the tension in each rope is equal to the weight that it holds up.

UTF-8 U+6211 U+662F wrote:Yep, your turn