Re: Reach for the Stars B
Posted: March 11th, 2012, 4:50 pm
I don't believe they were using Yerkes. I'm almost positive they were using Harvard's method. It was multiple choice and they were all letters. I think it was A, B, and O.
All I can remember is that the top two scores were tied with 95. I don't remember the rest.Epicfail21 wrote:Does anyone know have any scores for the R.C. Murphy/P. J. Gelinas Scrimmage?
I'm just little curious to see how everyone else did on that test.
Thank you very much!pjgscioisamazing wrote:All I can remember is that the top two scores were tied with 95. I don't remember the rest.Epicfail21 wrote:Does anyone know have any scores for the R.C. Murphy/P. J. Gelinas Scrimmage?
I'm just little curious to see how everyone else did on that test.
I took it by myself and I got an 88. But I did not know anything about standard candles and all that, and now I do. SO my score should have been 5-6 points higher.Epicfail21 wrote:Does anyone know have any scores for the R.C. Murphy/P. J. Gelinas Scrimmage?
I'm just little curious to see how everyone else did on that test.
The actual calculations of an objects position based upon these coordinates involves a fair amount of trigonometry which you would likely not be expected to know for this event. However, the the right ascension is the local sidereal time when the star reaches its peak altitude. This is a clock that runs a few minutes shorter than 24 hours to have a 364 day year accounting for the suns relative motion through the celestial sphere, which the normal clock is designed to keep at the same time. This time is also unique the observers longitude to perfectly account for it, as opposed to the rougher system of time zones. Declination can be used a little more easily with the observer's latitude. It tells you that the North Celestial Pole (or south if in the southern hemisphere) is at an angle to the horizon equal to your latitude. The celestial equator will be be at that angle to the zenith, and the complement of that angle to the horizon. The complement of your latitude will also tell you whether a star is circumpolar. (Eg at 40 degrees N, and star between 50 and 90 degrees declination will be circumpolar.) Finally, the negative complement of your latitude will tell you how far or south (oppose of your hemisphere) you can see in the celestial sphere. (So at 40 degrees I can see stars from -50 to 90 declination). This could also be used to see a star, as if I wanted to see a star at -80 declination, I know I would need to travel below 10 degrees North to be able to see it at all. Also for why it would be useful with a star chart: general purpose sky maps will often use this system for a grid, so you might be able to use the coordinates to find it quicker. (Or maybe a chart they give your in competition would have some coordinates that would help you identify).ilovecatsyl wrote:Alright thanks!
Back to that right ascension and declination thing:
So is the right ascension the amount of time from which the star/constellation rises and sets? If so how does tie in with longitude and a star chart?
Declination makes a little more sense. I'm pretty sure it's the latitude in which the star/constellation appears in?