Sorry, neither are correct. As a hint, phase is the key word here.Avogadro wrote:jkang wrote:A wave has a phase velocity of 2c (where c = the speed of light in a vacuum). How is this possible?If neither of those is true then I'm clueless.I have two possible explanations: 1. The wave has entered a theoretical material with a refractive index of 0.5. 2. The wave manages to have an incredibly short period.
Optics B/C
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Re: Optics B/C
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Re: Optics B/C
jkang wrote:Sorry, neither are correct. As a hint, phase is the key word here.Avogadro wrote:jkang wrote:A wave has a phase velocity of 2c (where c = the speed of light in a vacuum). How is this possible?If neither of those is true then I'm clueless.I have two possible explanations: 1. The wave has entered a theoretical material with a refractive index of 0.5. 2. The wave manages to have an incredibly short period.
The Theory of Relativity says that information cannot travel faster than the speed of light. The refractive index is a measure of the phase velocity of light, which does not carry information, so it is able to be less than 1.
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This is correct. Because phase velocity doesn't contain information, it has the ability to travel faster than c. The Wikipedia for refractive index has your answer almost word for word. Your turn!Adi1008 wrote:jkang wrote:Sorry, neither are correct. As a hint, phase is the key word here.Avogadro wrote:If neither of those is true then I'm clueless.I have two possible explanations: 1. The wave has entered a theoretical material with a refractive index of 0.5. 2. The wave manages to have an incredibly short period.The Theory of Relativity says that information cannot travel faster than the speed of light. The refractive index is a measure of the phase velocity of light, which does not carry information, so it is able to be less than 1.
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Re: Optics B/C
What is the smallest time delay required between two waves of 400nm light to obtain complete destructive interference?jkang wrote:This is correct. Because phase velocity doesn't contain information, it has the ability to travel faster than c. The Wikipedia for refractive index has your answer almost word for word. Your turn!Adi1008 wrote:jkang wrote: Sorry, neither are correct. As a hint, phase is the key word here.The Theory of Relativity says that information cannot travel faster than the speed of light. The refractive index is a measure of the phase velocity of light, which does not carry information, so it is able to be less than 1.
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You can answer I just wanted to give it a shot.Adi1008 wrote: What is the smallest time delay required between two waves of 400nm light to obtain complete destructive interference?
6.67*10^-16 seconds. This is using the distance over time definition of the speed of light with a 200nm distance to create fully destructive interference.
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Re: Optics B/C
That's correct; your turn!Tom_MS wrote:You can answer I just wanted to give it a shot.Adi1008 wrote: What is the smallest time delay required between two waves of 400nm light to obtain complete destructive interference?6.67*10^-16 seconds. This is using the distance over time definition of the speed of light with a 200nm distance to create fully destructive interference.
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A certain lens has an index of refraction of 1.5, a front lens radius of 0.09 m, and a back surface lens of -0.04 m according to the cartesian sign convention. If it is 0.10 m thick, determine the front vertex power.Adi1008 wrote:That's correct; your turn!
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Using the lensmakers formula and its derivation for thick lenses, I came up with an answer of 13.42 dioptersTom_MS wrote:A certain lens has an index of refraction of 1.5, a front lens radius of 0.09 m, and a back surface lens of -0.04 m according to the cartesian sign convention. If it is 0.10 m thick, determine the front vertex power.Adi1008 wrote:That's correct; your turn!
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Almost. To find the front vertex power you need to subtract the equivalent focal length by the distance from the front of the lens to the first principal plane.Sean_Sylvester1 wrote:Using the lensmakers formula and its derivation for thick lenses, I came up with an answer of 13.42 dioptersTom_MS wrote:A certain lens has an index of refraction of 1.5, a front lens radius of 0.09 m, and a back surface lens of -0.04 m according to the cartesian sign convention. If it is 0.10 m thick, determine the front vertex power.Adi1008 wrote:That's correct; your turn!
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Is it 64 diopters then? Since the equivalent focal length is the inverse of power and then subtract .09 from thatTom_MS wrote:Almost. To find the front vertex power you need to subtract the equivalent focal length by the distance from the front of the lens to the first principal plane.Sean_Sylvester1 wrote:Using the lensmakers formula and its derivation for thick lenses, I came up with an answer of 13.42 dioptersTom_MS wrote: A certain lens has an index of refraction of 1.5, a front lens radius of 0.09 m, and a back surface lens of -0.04 m according to the cartesian sign convention. If it is 0.10 m thick, determine the front vertex power.
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