Yeah, when using hide boxes, what text appears automatically and what text is hidden must be separated by the "|" symbol (you have to have something be automatically visible, so if you put ".|(your answer)" in the hide syntax you would get:)Alex-RCHS wrote:New to the forum... I hope I'm doing this "hide" thing right.
Answer: ~~When the angle of incidence is greater than the critical angle.~~
Edit: I'm not. Apologies.
When the angle of incidence is greater than the critical angle.
Alex-RCHS wrote:When light moves from a vacuum to a certain piece of glass its velocity slows to 1.98 x 10^8 meters per second. What is the index of refraction of the piece of glass?
[math]c = 3 \times 10^8 m/s, v = 1.98 \times 10^8 m/s, n= \frac{c}{v} = 1.52[/math] Adi1008 wrote:A source of light is located at a distance of 0.72m below the surface of water (n = 1.33). The light emerges at the surface into air (n=1.00) after undergoing refraction at the surface. Show that all the emerging light is all within a circle at the surface, and calculate the radius of the circle.
Also, sorry for taking so long to respond :/
0.82m
John Richardsim wrote:What is the power of a lens with a focal length of 8.40 centimeters?
Power (D) = 100/Focal Length (cm) Sooo approx: 11.9 dioptres
Good, your turn.Fluorine wrote:John Richardsim wrote:What is the power of a lens with a focal length of 8.40 centimeters?Power (D) = 100/Focal Length (cm) Sooo approx: 11.9 dioptres