So does we start one or does a mod?
Either way, I think this should be the first question (remember, answers have to be powers of 10): 70!
Not really, a "typical" fermi question, but it requires estimation skills either way.
Also, it may be beneficial to memorize the logs of a few small prime numbers for this problem.
zxcvb wrote:Are you allowed anything in with you (paper, pencil, calculator)?
I don't have the rules yet, but I'd certainly assume you're allowed a pencil... As for the calculator, I'd guess no, because you're more or less just multiplying orders of magnitude- i.e., adding.
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This event is going to be fun. If any of you are interested in a more precise and less "silly" (by that I only meant the type of problems) form of Fermi - i.e. the original Fermi problem with the atomic bomb, and things like that, you should check out Caltech's Order of Magnitude Physics class - http://www.its.caltech.edu/~oom/ is the link. I don't think it's a good study resource for Fermi as an event, but it's fun to go through, and for me, that's more important.
And by the way, 70! is 10^106. I say this because a couple months ago, I was evaluating factorials and my calculator stopped at 66 or 67 factorial, suggesting that that's where you hit 10^100, so sqrt(67) * 68 * 69 * 70 = 70^3.5 = 343000 * sqrt(70) = 3e6.
Angstrom wrote:This event is going to be fun. If any of you are interested in a more precise and less "silly" (by that I only meant the type of problems) form of Fermi - i.e. the original Fermi problem with the atomic bomb, and things like that, you should check out Caltech's Order of Magnitude Physics class - http://www.its.caltech.edu/~oom/ is the link. I don't think it's a good study resource for Fermi as an event, but it's fun to go through, and for me, that's more important.
And by the way, 70! is 10^106. I say this because a couple months ago, I was evaluating factorials and my calculator stopped at 66 or 67 factorial, suggesting that that's where you hit 10^100, so sqrt(67) * 68 * 69 * 70 = 70^3.5 = 343000 * sqrt(70) = 3e6.
Actually, 70! is about 10^100.
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<quizbowl> ey kid ya want some shortbread
<EASTstroudsburg13> I don't know why, but I just can't bring myself to delete this post.
quiz is right. I just checked with the calculator on my computer. I got 1.198e100
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so for 2 it's actually saying 10 ^ (10^-10). 10^-10 is 1E-10, so the problem is really asking what is 10 ^(1E-10). 1E-10 is very close to 0 so your answer is 0. You just placed the parentheses incorrectly when you were doing it in your head.
3 is 10^(10^(10^-10)), 10^-10 is 1E-10, 10^(1E-10) is 1 as seen above, so the answer is 1.
4 is 10^(10^(10^(10^-10))), use the stuff from three to get down to 10^(10^1) which is 10^10 so the answer is 10.
I hope that helped. I think your only problem was your idea of where the parentheses would go.
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(remember, answers have to be powers of 10): 70!
