John Richardsim wrote:Use c=3.00*10^8
What is the wavelength (in nm) of light with a frequency of 4.40*10^2 THz? What color of visible light does this correspond to?
682 nm, which corresponds to red light.
John Richardsim wrote:Use c=3.00*10^8
What is the wavelength (in nm) of light with a frequency of 4.40*10^2 THz? What color of visible light does this correspond to?
682 nm, which corresponds to red light.
Yep, good. Your turn.0ddrenaline wrote:John Richardsim wrote:Use c=3.00*10^8
What is the wavelength (in nm) of light with a frequency of 4.40*10^2 THz? What color of visible light does this correspond to?682 nm, which corresponds to red light.
0ddrenaline wrote:
The geometry of a compound microscope, which consists of two converging lenses, is shown in the picture above. The objective lens and the eyepiece lens have focal lengths of 2.8 mm and 3.3 cm, respectively. If an object is located at 3.0 mm from the objective lens, where is the final image located?
(sorry about the image quality)
11 cm behind the objective lens (18 cm behind the eyepiece).
You're right. Go aheadJohn Richardsim wrote:0ddrenaline wrote:
The geometry of a compound microscope, which consists of two converging lenses, is shown in the picture above. The objective lens and the eyepiece lens have focal lengths of 2.8 mm and 3.3 cm, respectively. If an object is located at 3.0 mm from the objective lens, where is the final image located?
(sorry about the image quality)11 cm behind the objective lens (18 cm behind the eyepiece).
John Richardsim wrote:Light with a wavelength of 6.00*10^2 nm in a vacuum enters water (n=1.33). What is the wavelength of the light in water?
4.51*10^2 nm
Yep, your turn.0ddrenaline wrote:John Richardsim wrote:Light with a wavelength of 6.00*10^2 nm in a vacuum enters water (n=1.33). What is the wavelength of the light in water?4.51*10^2 nm
0ddrenaline wrote:What is the effect of a comatic aberration on a lens' image?
The image appears to have a "tail" due to different magnifications along the lens (also, which part of the rules does this fall under?)
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